27=(2w^2)-3w

Solution for 27=(2w^2)-3w equation:

27=(2w^2)-3w

We move all terms to the left:

27-((2w^2)-3w)=0

We get rid of parentheses

-2w^2+3w+27=0

a = -2; b = 3; c = +27;
Δ = b2-4ac
Δ = 32-4·(-2)·27
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*-2}=\frac{-18}{-4}
=4+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*-2}=\frac{12}{-4}
=-3
$